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Re: Differencing two equations

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  • Subject: [mg129783] Re: Differencing two equations
  • From: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>
  • Date: Wed, 13 Feb 2013 04:50:11 -0500 (EST)
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Dear community,

I have seen in this thread a lot of nice approaches that I really admire, but
writing simply:

eq2 = b == s;
eq1 = a == r;

eq1[[1]] - eq2[[1]] == eq1[[2]] - eq2[[2]]

a - b == r - s

is shorter.

Have fun, Alexei



> a==r
> b==s

> I'd like to get:
> a-b == r-s

Hi.   Here are a few ideas.

v={a==r,b==s};

Equal@@Subtract@@@{v[[All,1]],v[[All,-1]]}
a-b==r-s

Equal@@Subtract@@@Transpose[List@@@v]
a-b==r-s

{*  I like Inner  *)

Inner[Subtract,a==r,b==s,Equal]
a-b==r-s

// or...

Inner[Subtract,v[[1]],v[[2]],Equal]
a-b==r-s


= = = = = = = = = =
HTH   :>)
=E2=80=A8Dana DeLouis
Mac & Mathematica 9
=E2=80=A8= = = = = = = = = =





On Sunday, February 10, 2013 3:35:06 AM UTC-5, G B wrote:
> I'm brand new to Mathematica, so I apologize for the naive questions...
>
>
>
> I'm trying to figure out how to difference two equations.  Basically if I=
 have:
>
> a==r
>
> b==s
>
>
>
> I'd like to get:
>
> a-b == r-s
>
>
>
> What I'm getting is more like (a==r) - (b==s).  I'm not sure how that's a useful result, but is there a function to do what I'm looking for?
>
>
>
> A quick search of the archives seem to bring up ways of doing this from using transformation rules to swap heads to unlocking the Equals operator and hacking its behavior.  I'd like to avoid doing that kind of rewiring for a simple operation, and I'd like to keep the syntax clean.
>
>
>
> The Core Language documentation makes a big point of how everything is basically a list with different heads.  In this case, what I'm trying to do would work if it were treated as a list ({a,b}-{r,s} returns {a-b,r-s}) but doesn't work under Equal.
>
>
>
> Thanks for any suggestions.



Alexei BOULBITCH, Dr., habil.
IEE S.A.
ZAE Weiergewan,
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L-5326 Contern, LUXEMBOURG

Office phone :  +352-2454-2566
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e-mail: alexei.boulbitch at iee.lu






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