Re: List:{1}, {2,3},{4,5,6}....
- To: mathgroup at smc.vnet.net
- Subject: [mg129417] Re: List:{1}, {2,3},{4,5,6}....
- From: Bob Hanlon <hanlonr357 at gmail.com>
- Date: Fri, 11 Jan 2013 22:26:44 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
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- References: <20130111023936.D243068E0@smc.vnet.net>
m = 5;
t1 = Timing[
list1 = Table[
i + 1, {n, 1, m}, {i, n (n - 1)/2, n (n - 1)/2 + n - 1}];][[1]]
0.000083
t2 = Timing[
list2 = Table[Range[n (n - 1)/2 + 1, n (n + 1)/2], {n, m}];][[1]]
0.000054
t1/t2
1.5
list1 == list2
True
m = 1000;
t3 = Timing[
list3 = Table[
i + 1, {n, 1, m}, {i, n (n - 1)/2, n (n - 1)/2 + n - 1}];][[1]]
0.368475
t4 = Timing[
list4 = Table[Range[n (n - 1)/2 + 1, n (n + 1)/2], {n, m}];][[1]]
0.010008
t3/t4
36.82
list3 == list4
True
Bob Hanlon
On Thu, Jan 10, 2013 at 9:39 PM, hknetman <hknetman at hotmail.com> wrote:
> I use the command
> list = Table[i + 1, {n, 1, 5}, {i, n (n - 1)/2, n (n - 1)/2 + n - 1}]
> to get the following result:
> {{1}, {2, 3}, {4, 5, 6}, {7, 8, 9, 10}, {11, 12, 13, 14, 15}}
>
> Is there any better method?
>
> Thanks a lot.
>
- References:
- List:{1}, {2,3},{4,5,6}....
- From: hknetman <hknetman@hotmail.com>
- List:{1}, {2,3},{4,5,6}....