       Re: Making (a*\[Theta]11)/(1+a^2) into (a/(1+a^2))*\[Theta]11

• To: mathgroup at smc.vnet.net
• Subject: [mg131307] Re: Making (a*\[Theta]11)/(1+a^2) into (a/(1+a^2))*\[Theta]11
• From: "djmpark" <djmpark at comcast.net>
• Date: Wed, 26 Jun 2013 01:03:51 -0400 (EDT)
• Delivered-to: l-mathgroup@mail-archive0.wolfram.com
• Delivered-to: l-mathgroup@wolfram.com
• Delivered-to: mathgroup-outx@smc.vnet.net
• Delivered-to: mathgroup-newsendx@smc.vnet.net
• References: <31415507.250690.1372209487404.JavaMail.root@m06>

```You have to use something like HoldForm and this may or may not interfere
with further calculation.

You could use:

a \[Theta]11/(1 + a^2);
% /. (r = Coefficient[%, \[Theta]11]) :>

a/(1+a^2) \[Theta]11

The TraditionalForm is necessary to get the desired order of the two
factors.

With the Presentations Application you could use:

<<Presentations`

a \[Theta]11/(1 + a^2) //

a/(1+a^2) \[Theta]11

And I'm sure you'll get a number of other answers.

David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/index.html

Hi, I have a formatting question.

In the output of an equation I am getting the term (a*\[Theta]11)/(1+a^2).
However, \[Theta]11 is the variable of interest here, and I would like the
term to be written as as a coefficient times \[Theta]11 and not include
\[Theta]11 in the ratio.  That is, I would like the output to read
(a/(1+a^2))*\[Theta]11 instead.  Does anyone have an idea of how I might be
able to do this?  Thanks.

```

• Prev by Date: Re: automatic grid
• Next by Date: Re: What is f? Advanced question
• Previous by thread: Re: Decoupling E and I
• Next by thread: Making (a*\[Theta]11)/(1+a^2) into (a/(1+a^2))*\[Theta]11