Re: Query regarding Function
- To: mathgroup at smc.vnet.net
- Subject: [mg130142] Re: Query regarding Function
- From: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>
- Date: Thu, 14 Mar 2013 07:12:49 -0400 (EDT)
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- Delivered-to: l-mathgroup@wolfram.com
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Dear all,
Case1: In the following code
Clear[f,x,y]
g=Function[{x,y},x^2+2xy][b,a]
The output is found to be b^2+2 xy
Case2: But for the code
Clear[f,x,y]
g=Function[{x,y},x^2+2y][b,a]
The output is 2 a+b^2
Hence my query is why in case 1 x*y is not replaced by b and a whereas in case 2 it got replaced ?
Regards,
rc
Hi, Rahul,
Mathematica understands xy as a single new symbol, and, therefore, it does not interpret it as a product. If you want it to be multiplication you should make a space between x and y.
Then it works. Compare: this is your function
Clear[f, x, y]
g = Function[{x, y}, x^2 + 2 xy][b, a]
b^2 + 2 xy
and this is the same, but with the space between x and y:
Clear[f, x, y]
g = Function[{x, y}, x^2 + 2 x y][b, a]
2 a b + b^2
However, I prefer to put the sign "*" between x and y. Since it becomes quite clear from the first glance, what is x*y. Like this:
Clear[f, x, y]
g = Function[{x, y}, x^2 + 2 x*y][b, a]
2 a b + b^2
Have fun, Alexei
Alexei BOULBITCH, Dr., habil.
IEE S.A.
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