Re: Through[Divide[f1, f2][x]]
- To: mathgroup at smc.vnet.net
- Subject: [mg130930] Re: Through[Divide[f1, f2][x]]
- From: Andrzej Kozlowski <akozlowski at gmail.com>
- Date: Sun, 26 May 2013 05:06:20 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-outx@smc.vnet.net
- Delivered-to: mathgroup-newsendx@smc.vnet.net
- References: <20130525093819.33DE96347@smc.vnet.net>
On 25 May 2013, at 11:38, Andres Guzman =
<andres.guzman.fernandez at gmail.com> wrote:
> $Version
> 8.0 for Linux x86 (64-bit) (October 10, 2011)
>
> Through[Divide[f1, f2][x]]
> f1[x] (1/f2)[x]
>
> (* When what I want is: Divide[f1[x],f2[x]] . An uncomfortable =
consequence of the way Mathematica treats division.*)
>
> Divide[f1, f2] // FullForm
> Times[f1, Power[f2, -1]]
>
One way round this sort of problems is to Block Divide:
Block[{Divide}, Through[Divide[f1, f2][x]]]
f1[x]/f2[x]
Of course this involves extra typing but then if you wanted to save =
yourself typing you could have just typed f1[x]/f2[x].
Andrzej Kozlowski
- References:
- Through[Divide[f1, f2][x]]
- From: Andres Guzman <andres.guzman.fernandez@gmail.com>
- Through[Divide[f1, f2][x]]