Re: a simple question
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- Subject: [mg131729] Re: a simple question
- From: Murray Eisenberg <murray at math.umass.edu>
- Date: Tue, 24 Sep 2013 04:17:35 -0400 (EDT)
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Do you mean you want to solve that equation for h? (That's a different thing than "evaluating it", which would not be possible since the left hand side is not the sort of expression to which you can assign a value -- and what does is to assign a value. Whereas == denotes an equality.) Perhaps you mean something like the following: Solve[A Log[h]/h - x == 0, h] The result you'll get gives the solution as: h -> -((A*ProductLog[-(x/A)])/x This may or may not be of use to you, since ProductLog is a not an "elementary" function. Do A and x have some specific values? By the way, it's a bad idea to use names in Mathematica that are, or begin with, an upper-case letter -- because that risks confounding them with the names of built-in objects. On Sep 23, 2013, at 9:59 PM, Dhaneshwar Mishra <dhaneshwarmishra at gmail.com> wrote: > > I would like to evaluate A*Log[h]/h -x=0 for h, can any body help me doing so? > > I am beginner for Mathematica. --- Murray Eisenberg murray at math.umass.edu Mathematics & Statistics Dept. Lederle Graduate Research Tower University of Massachusetts 710 North Pleasant Street Amherst, MA 01003-9305
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- a simple question
- From: Dhaneshwar Mishra <dhaneshwarmishra@gmail.com>
- a simple question