Re: Very simple question
- To: mathgroup at smc.vnet.net
- Subject: [mg132558] Re: Very simple question
- From: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>
- Date: Fri, 11 Apr 2014 02:11:09 -0400 (EDT)
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I've been away from Mathematica for about 7 years. Can anyone tell me why function fx gives an error message but fy does not? They look functionally the same to me. Please send me an email about this. fx[ptl_] := Module[{x1, y1, x2, y2, x3, y3}, Print[pt1]; x1 = pt1[[1, 1]]; y1 = pt1[[1, 2]]; x2 = pt2[[2, 1]]; y2 = pt2[[2, 2]]; x3 = pt3[[3, 1]]; y3 = pt3[[3, 2]]; Print[x1, y1, x2, y2, x3, y3]; ] fx[{{1, 2}, {3, 5}, {4, 7}}] fy[pt1_] := Module[{zz, x1, y1, x2, y2, x3, y3}, zz = pt1; Print[zz]; x1 = zz[[1, 1]]; y1 = zz[[1, 2]]; x2 = zz[[2, 1]]; y2 = zz[[2, 2]]; x3 = zz[[3, 1]]; y3 = zz[[3, 2]]; Print[x1, y1, x2, y2, x3, y3] ] fy[{{1, 2}, {3, 5}, {4, 7}}] Thank you. Steve Gray stevebg at roadrunner.com Hi, Stephen, The answer is also simple: the body of the function fx calls pt2 and pt3 that are not defined anywhere. It confuses Mathematica. If you replace fx as follows: fx[pt1_] := Module[{x1, y1, x2, y2, x3, y3}, x1 = pt1[[1, 1]]; y1 = pt1[[1, 2]]; x2 = pt1[[2, 1]]; y2 = pt1[[2, 2]]; x3 = pt1[[3, 1]]; y3 = pt1[[3, 2]]; Print[x1, y1, x2, y2, x3, y3]] Which is probably what you intended, it will return the result. In messages though. To see the result on the screen it is better to do something like the following: fz[pt1_] := Module[{x1, y1, x2, y2, x3, y3}, x1 = pt1[[1, 1]]; y1 = pt1[[1, 2]]; x2 = pt1[[2, 1]]; y2 = pt1[[2, 2]]; x3 = pt1[[3, 1]]; y3 = pt1[[3, 2]]; {x1, y1, x2, y2, x3, y3}] fz[{{1, 2}, {3, 5}, {4, 7}}] {1, 2, 3, 5, 4, 7} Have fun, Alexei Alexei BOULBITCH, Dr., habil. IEE S.A. ZAE Weiergewan, 11, rue Edmond Reuter, L-5326 Contern, LUXEMBOURG Office phone : +352-2454-2566 Office fax: +352-2454-3566 mobile phone: +49 151 52 40 66 44 e-mail: alexei.boulbitch at iee.lu