MathGroup Archive 1990

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Re: High precision floating point considered hazardous


I tried this problem....

        a = 1.1111111111111111
        Do[a=2a-a,{55}]

on versions 1.1 and 1.2.  I did obtain 0 on version 1.2, but there was no
error on 1.1..i.e., I did not obtain 0!  Seems like a bug in version 1.2.





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