Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
1990
*January
*February
*March
*April
*May
*June
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 1990

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Integrating Gaussians

  • To: mathgroup at yoda.ncsa.uiuc.edu
  • Subject: Re: Integrating Gaussians
  • From: uunet!wri!keiper
  • Date: Mon, 4 Jun 90 14:23:53 CDT

One way to trick Mathematica into evaluating Erf[] at infinities when the
sign of the argument is unknown is to do the following:

In[1]:= Unprotect[Erf]

Out[1]= {Erf}

In[2]:= Erf[DirectedInfinity[1] * ___] = 1

Out[2]= 1
 
In[3]:= Erf[DirectedInfinity[-1] * ___] = -1

Out[3]= -1

In[4]:= Integrate[Exp[-x^2/(2 sigma^2)],{x,-Infinity,Infinity}]

Out[4]= Sqrt[2] Sqrt[Pi] sigma

It will still be smart enough to figure out what to do with signed numbers:

In[5]:= Erf[DirectedInfinity[1] * (-2)]

Out[5]= -1

but if you have in mind a negative value for sigma it will give the wrong
answer.


  • Prev by Date: newsgroup vs. digest vs. status quo
  • Next by Date: Superimposed plots
  • Previous by thread: newsgroup vs. digest vs. status quo
  • Next by thread: Integrating Gaussians