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Three dimensional countours

• To: mathgroup at smc.vnet.net
• Subject: [mg2125] Three dimensional countours
• From: Paul Smith <pw_smith at Postoffice.SandyBay.utas.edu.au>
• Date: Wed, 4 Oct 1995 01:55:03 -0400

I am an honours student at the Uni. of Tasmania (Australia). 
My honours project requires me to plot out a set of countours 
in order to define a three dimensional surface.
An example is as follows:
	
	(My/900)^1.5 + (Mx/900)^1.5 = 1.0

This countour can be found for different defining conditions
thus simulating a 3D surface. However, as I am a novice
mathematica user and the Math's dep. arn't interested in 
helping me as I am an engineering student, I was wondering if
you could start me off in some way.

		Thanks - Paul.