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Re: Need help with solving problem



On Wed, 27 Nov 1996, Ingimar V=F6lundarson wrote:

> Can anyone help me with this problem?
>=20
> (4^x)+(2^x)-2=3D0
>=20
> Everyone can see that x=3D0 but:
>=20
> (4^x)+(2^x)-2=3D0 =3D>
> 2*(2^x)+(2^x)-2=3D0 =3D>
>
> more stuff

Hi Ingimar,

The problem here is that

4^x !=3D 2*(2^x)

Instead,

4^x =3D 2^(2*x) =3D (2^x)^2

Carl Woll



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