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Re: Need help with solving problem
- To: mathgroup at smc.vnet.net
- Subject: [mg5400] Re: [mg5339] Need help with solving problem
- From: "C. Woll" <carlw at u.washington.edu>
- Date: Thu, 5 Dec 1996 14:50:33 -0500
- Sender: owner-wri-mathgroup at wolfram.com
On Wed, 27 Nov 1996, Ingimar V=F6lundarson wrote:
> Can anyone help me with this problem?
>=20
> (4^x)+(2^x)-2=3D0
>=20
> Everyone can see that x=3D0 but:
>=20
> (4^x)+(2^x)-2=3D0 =3D>
> 2*(2^x)+(2^x)-2=3D0 =3D>
>
> more stuff
Hi Ingimar,
The problem here is that
4^x !=3D 2*(2^x)
Instead,
4^x =3D 2^(2*x) =3D (2^x)^2
Carl Woll
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