Re: Need help with solving problem

*To*: mathgroup at smc.vnet.net*Subject*: [mg5360] Re: [mg5339] Need help with solving problem*From*: jpk at apex.mpe.FTA-Berlin.de (Jens-Peer Kuska)*Date*: Thu, 5 Dec 1996 14:50:10 -0500*Sender*: owner-wri-mathgroup at wolfram.com

> From mathgroup-adm at smc.vnet.net Wed Nov 27 16:34:00 1996 > From: ingimar.volundarson at mailbox.swipnet.se (Ingimar V\vlundarson) To: mathgroup at smc.vnet.net > To: mathgroup at smc.vnet.net > Subject: [mg5339] Need help with solving problem > Content-Length: 399 > X-Lines: 24 > > Can anyone help me with this problem? > > (4^x)+(2^x)-2=0 > > Everyone can see that x=0 but: > > (4^x)+(2^x)-2=0 => > 2*(2^x)+(2^x)-2=0 => Yes ? really that are new kind of calculation rules. I think (4^x)== 2^(2x) ==2^x*2^x and You get y^2+y-2==0 finaly one gets the correct solution x-> I (Pi-I*Log[2])/Log[2] Hope that helps Jens