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Re: Need help with solving problem

• To: mathgroup at smc.vnet.net
• Subject: [mg5360] Re: [mg5339] Need help with solving problem
• From: jpk at apex.mpe.FTA-Berlin.de (Jens-Peer Kuska)
• Date: Thu, 5 Dec 1996 14:50:10 -0500
• Sender: owner-wri-mathgroup at wolfram.com

> From mathgroup-adm at smc.vnet.net Wed Nov 27 16:34:00 1996
> From: ingimar.volundarson at mailbox.swipnet.se (Ingimar V\vlundarson)
To: mathgroup at smc.vnet.net
> To: mathgroup at smc.vnet.net
> Subject: [mg5339] Need help with solving problem
> Content-Length: 399
> X-Lines: 24
> 
> Can anyone help me with this problem?
> 
> (4^x)+(2^x)-2=0
> 
> Everyone can see that x=0 but:
> 
> (4^x)+(2^x)-2=0 =>
> 2*(2^x)+(2^x)-2=0 =>

Yes ? really that are new kind of calculation rules.
I think

 (4^x)== 2^(2x) ==2^x*2^x and You get
 y^2+y-2==0

finaly one gets the correct solution
x-> I (Pi-I*Log[2])/Log[2]

Hope that helps
Jens