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MathGroup Archive 1996

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Re: Inverse????

  • To: mathgroup at smc.vnet.net
  • Subject: [mg5501] Re: [mg5477] Inverse????
  • From: Sherman Reed <Sherman.Reed at worldnet.att.net>
  • Date: Sat, 14 Dec 1996 19:26:05 -0500
  • Sender: owner-wri-mathgroup at wolfram.com

At 08:15 AM 12/11/96 +0000, you wrote:
>A matrix a={{0,0,1},{0,0,1},{1,1,1}} which is singular in Z_2, but  
>Inverse commands gives the "result": 
>
>
>Inverse[a,Modulus->2]=
>{{0, 1, 1}, {1, 1, 0}, {1, 0, 0}}. 
>
>
>Is anything wrong ?
>
>
>
>Houshou  
>
>
I got the same result as you on 2.2.3, 
but on 3.0 I recieved the following

Inverse::"sing": 
    "Matrix \!\({\({0, 0, 1}\), \({0, 0, 1}\), 
                \({1, 1, 1}\)}\) is singular."

I assume an error in 2.2.3 that has been fixed
in 3.0.  Wolfram will probably comment

sherman reed




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