Re: Inverse????

*To*: mathgroup at smc.vnet.net*Subject*: [mg5501] Re: [mg5477] Inverse????*From*: Sherman Reed <Sherman.Reed at worldnet.att.net>*Date*: Sat, 14 Dec 1996 19:26:05 -0500*Sender*: owner-wri-mathgroup at wolfram.com

At 08:15 AM 12/11/96 +0000, you wrote: >A matrix a={{0,0,1},{0,0,1},{1,1,1}} which is singular in Z_2, but >Inverse commands gives the "result": > > >Inverse[a,Modulus->2]= >{{0, 1, 1}, {1, 1, 0}, {1, 0, 0}}. > > >Is anything wrong ? > > > >Houshou > > I got the same result as you on 2.2.3, but on 3.0 I recieved the following Inverse::"sing": "Matrix \!\({\({0, 0, 1}\), \({0, 0, 1}\), \({1, 1, 1}\)}\) is singular." I assume an error in 2.2.3 that has been fixed in 3.0. Wolfram will probably comment sherman reed