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ArcTan[-Cotan[theta]]


I'm trying to solve:

     1) ArcTan[-Cotan[theta]]

Along the way, I tried to get Mathematica to tell me that

   theta = ArcTan[Tan[theta]]    (or at least plus a factor of 2*Pi.)

How could I do this?

Thanks.

-- Stephen

=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
Stephen Boulet
stephenbou at aol.com
http://members.aol.com/stephenbou/
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=

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