ArcTan[-Cotan[theta]]

*To*: mathgroup at smc.vnet.net*Subject*: [mg4909] ArcTan[-Cotan[theta]]*From*: stephenbou at aol.com (StephenBou)*Date*: Fri, 4 Oct 1996 00:17:44 -0400*Organization*: America Online, Inc. (1-800-827-6364)*Sender*: owner-wri-mathgroup at wolfram.com

I'm trying to solve: 1) ArcTan[-Cotan[theta]] Along the way, I tried to get Mathematica to tell me that theta = ArcTan[Tan[theta]] (or at least plus a factor of 2*Pi.) How could I do this? Thanks. -- Stephen =+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+= Stephen Boulet stephenbou at aol.com http://members.aol.com/stephenbou/ =+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+= ==== [MESSAGE SEPARATOR] ====