Re: mathematica problem

• To: mathgroup at smc.vnet.net
• Subject: [mg7609] Re: [mg7540] mathematica problem
• From: Richard Finley <trfin at fiona.umsmed.edu>
• Date: Thu, 19 Jun 1997 15:53:25 -0400 (EDT)
• Sender: owner-wri-mathgroup at wolfram.com

```Stephanie,

I presume the region you are interested in is bounded by the inverse Sine
function which should be called using ArcSin and not Sin^-1....Sin[ x ]^-1
is just 1/Sin[x] and the volume you are talking about would be infinite.  If
you do want the region bounded by ArcSin (you don't say whether the x limits
you are interested in are from 0 to 1 or from -1 to 1, but the principle is
the same) simply use:

Integrate[ Pi ArcSin[x]^2 , { x, 0, 1 } ]

or change the limits to -1 to 1 if you prefer....that should work.  Hope
that helps.
RF

At 07:37 PM 6/13/97 -0400, you wrote:
>Here is the word problem:
>
>Consider the region enclosed by y=sin^-1x, y=0, and x=1.  Find the volume
of the
>solid generated by revolving the region about the x-axis using
>a)  disks;
>b)  cylindrical shells.
>
>I do not understand how to do this on Mathematica, can you help?
>
>Sincerely,
>Stephanie Gill
>
>
>

```

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