Re: mathematica problem

*To*: mathgroup at smc.vnet.net*Subject*: [mg7609] Re: [mg7540] mathematica problem*From*: Richard Finley <trfin at fiona.umsmed.edu>*Date*: Thu, 19 Jun 1997 15:53:25 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Stephanie, I presume the region you are interested in is bounded by the inverse Sine function which should be called using ArcSin and not Sin^-1....Sin[ x ]^-1 is just 1/Sin[x] and the volume you are talking about would be infinite. If you do want the region bounded by ArcSin (you don't say whether the x limits you are interested in are from 0 to 1 or from -1 to 1, but the principle is the same) simply use: Integrate[ Pi ArcSin[x]^2 , { x, 0, 1 } ] or change the limits to -1 to 1 if you prefer....that should work. Hope that helps. RF At 07:37 PM 6/13/97 -0400, you wrote: >Here is the word problem: > >Consider the region enclosed by y=sin^-1x, y=0, and x=1. Find the volume of the >solid generated by revolving the region about the x-axis using >a) disks; >b) cylindrical shells. > >I do not understand how to do this on Mathematica, can you help? > >Sincerely, >Stephanie Gill > > >