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Re: rules->function


In article <5mepea$aom at smc.vnet.net>, Lord of Darkness
<j.biddiscombe at rl.ac.uk> wrote:

> If I solve a set of simultaneous equations and get a simple answer like
> zrule = z-> x^2 + y^2
> 
> but I then want to evaluate
> fn[x_,y_] := z + some more stuff.....

Try   fn[x_,y_] := z + some more stuff..... /.zrule

There may be a more efficient way of doing this.

> I tried saying
> 
> fn[x_,y_] := Replace[z,zrule] + .... 

Just a guess, but I bet Replace means "->", so zrule in the Replace[]
should just be x^2 + y^2.

-- 
Louis M. Pecora
pecora at zoltar.nrl.navy.mil
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