Re: FindRoot

*To*: mathgroup at smc.vnet.net*Subject*: [mg8917] Re: [mg8887] FindRoot*From*: seanross at worldnet.att.net*Date*: Thu, 2 Oct 1997 22:57:13 -0400*Sender*: owner-wri-mathgroup at wolfram.com

David Djajaputra wrote: > > I need to plot the root of a transcendental equation > > sin(x)=x/a, for a from 2 to 3. > > I can find the root for each a using FindRoot. But how do I make a > continuous plot > using FindRoot? > > Thanks a lot! > > David Djajaputra root[a_]:=x/.FindRoot[Sin[x]==x/a,{x,.5}] will do the trick. Note that the initial guess might need to be changed to something more appropriate. the /. notation means "such that". Since FindRoot returns a transformation rule, I use x such that x transforms to #### (x/.{x->###}.