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Re: FindRoot

• To: mathgroup at smc.vnet.net
• Subject: [mg8917] Re: [mg8887] FindRoot
• From: seanross at worldnet.att.net
• Date: Thu, 2 Oct 1997 22:57:13 -0400
• Sender: owner-wri-mathgroup at wolfram.com

David Djajaputra wrote:
> 
> I need to plot the root of a transcendental equation
> 
> sin(x)=x/a,     for a from 2 to 3.
> 
> I can find the root for each a using FindRoot. But how do I make a
> continuous plot
> using FindRoot?
> 
> Thanks a lot!
> 
> David Djajaputra


root[a_]:=x/.FindRoot[Sin[x]==x/a,{x,.5}]

will do the trick.  Note that the initial guess might need to be changed
to something more appropriate.  the /. notation means "such that". 
Since FindRoot returns a transformation rule, I use x such that x
transforms to #### (x/.{x->###}.