Re: A Recreational Endeavour

*To*: mathgroup at smc.vnet.net*Subject*: [mg8762] Re: [mg8751] A Recreational Endeavour*From*: Hans Havermann <haha at astral.magic.ca>*Date*: Sun, 21 Sep 1997 20:51:06 -0400*Sender*: owner-wri-mathgroup at wolfram.com

Dr. Wouter L.J. Meeussen writes: >If you put both x and y in the returned answer, then you get a "real" >permutation as result : containing all integers from 1 up to 4+3n, the first >n from x, the rest in y. Thank you for all this. It will take me a little time to go through it. The algorithm is perhaps a little more understandable from the perspective of its origin... Row01: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 ... Row02: 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 ... Row03: 4 2 5 6 7 8 9 10 11 12 13 14 15 16 17 ... Row04: 6 2 7 4 8 9 10 11 12 13 14 15 16 17 18 ... Row05: 8 7 9 2 10 6 11 12 13 14 15 16 17 18 19 ... Row06: 6 2 11 9 12 7 13 8 14 15 16 17 18 19 20 ... Row07: 13 12 8 9 14 11 15 2 16 6 17 18 19 20 21 ... Row08: 2 11 16 14 6 9 17 8 18 12 19 13 20 21 22 ... Row09: 18 17 12 9 19 6 13 14 20 16 21 11 22 2 23 ... Row10: 16 14 21 13 11 6 22 19 2 9 23 12 24 17 25 ... To generate Row'n+1' from Row'n': expel the n-th number (it is these expelled "diagonal" numbers that comprise my sought-after set); *rewrite* beginning with the first number to the right of the dropped number followed by the first number to the left (if any); then the second number to the right of the dropped number followed by the second number to the left (if any); and so on. The idea was proposed by Clark Kimberling as problem #1615 in the Canadian "Crux Mathematicorum" in 1991. He asks: (a) Is 2 eventually expelled? (b) Is every positive integer eventually expelled? In the March 1992 issue of Crux (Vol.18, #3), a solution to part (a) is given by Iliya Bluskov, who developed an algorithm for the general case and applies it for all n < 51. He notes that '19' is expelled in Row 49595. The editor of Crux comments on the general case, citing Richard and Andy Guy as having done work on it. Specifically, they had shown "that every integer up to 1200 is eventually expelled" with, for instance, '669' being expelled in Row 653494691. Richard also found several infinite "families" of expelled integers. *My* interest in all this: Having calculated a 4491 element set for x, we notice: Do[If[x[[i]]==i,Print[i]],{i,1,Length[x]}] 1 4 8 14 171 This immediately suggests: Do[If[x[[i]]<=Length[x],If[x[[i]]!=i,If[x[[x[[i]]]]==i,Print[i]]]],{i,1, Length[x]}] 813 985 In other words x[[813]]=985 and x[[985]]=813. So now I'm thinking: what other "loops" like this can we discover? My guess: not many (without some serious computing power). Some years ago, in Basic, I had calculated quite a few terms of the "loop" in which '2' finds itself [... 1523, 43, 25, 2, 3, 5, 10, 9, 20, ... ]. It is possible *algorithmically* to go forward (or backward) along this loop finding the next (or previous) term. I love the *asymmetry* of this sequence: Going forward, the next number is always guaranteed, never more than three times as large. Going backwards, who knows? There may not even be a previous number! We think we can understand why the numbers must get bigger (on average) as we move forward, *but* we must remind ourselves that we have gotten to '2' from some very large "ancestor" in the same process of moving forward! :-) I lost all my primary data on this a couple of years ago in a hard-drive crash. :-( Hans Havermann Rarebit Dreams http://astral.magic.ca/~haha/rarebit.html

**RE: A Recreational Endeavour**

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**RE: A Recreational Endeavour**

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