[Date Index] [Thread Index] [Author Index]

How to get the solution area of inequation?

• To: mathgroup@smc.vnet.net
• Subject: [mg11983] How to get the solution area of inequation?
• From: gis86806@cis.nctu.edu.tw (8623806)
• Date: Fri, 17 Apr 1998 03:40:20 -0400
• Organization: Dept. of Computer & Information Science, NCTU, Taiwan

I have three circles:

C1: (0,0) with radius r
C2: (a,0) with radius r/k
C3: (a+b Cos[\[Theta]], b Sin[\[Theta]]) with radius r/k

k is an integer and 0 <  a< r, 0 < [Theta] < Pi, also the center of C3
is in the intersection of C1 and C2.

If there is a possible general solution for C1 && C3 && !C2 ??

Thanks a lot!