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MathGroup Archive 1998

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How to get the solution area of inequation?


  • To: mathgroup@smc.vnet.net
  • Subject: [mg11983] How to get the solution area of inequation?
  • From: gis86806@cis.nctu.edu.tw (8623806)
  • Date: Fri, 17 Apr 1998 03:40:20 -0400
  • Organization: Dept. of Computer & Information Science, NCTU, Taiwan

I have three circles:

C1: (0,0) with radius r
C2: (a,0) with radius r/k
C3: (a+b Cos[\[Theta]], b Sin[\[Theta]]) with radius r/k

k is an integer and 0 <  a< r, 0 < [Theta] < Pi, also the center of C3
is in the intersection of C1 and C2.

If there is a possible general solution for C1 && C3 && !C2 ??

Thanks a lot!



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