- To: mathgroup at smc.vnet.net
- Subject: [mg13689] Fourier Transform
- From: Edward Neuman <edneuman at siu.edu>
- Date: Sat, 15 Aug 1998 04:39:20 -0400
- Organization: SIUC
- Sender: owner-wri-mathgroup at wolfram.com
Let f(x) = 1/x. If f is regarded as the generalized function, then its
Fourier transform is:
-Pi*I*Sign[t] (see, e.g., G.B.
Folland, "Fourier Analysis and Its Applications," p. 337).
Using Mathematica 3.0 we get:
FourierTransform[1/x, x, t]
2*I*Pi*(-(1/2) + UnitStep[t, ZeroValue -> 1/2]).
This agrees with the above result only if t = 0. Bug?
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