Re: Re: How do u go about doing this---?
Yes, Sorry, Thanks
> Oops Jens,
> you overlooked the fact that he wanted the sum of squares of the first
> derivative, not the sum of the second derivatives.
> Happens to the best of us, at least some of the time. I goof myself now &
> then, I know the feeling. But *do* go on replying. The least we, non-guru's,
> can do is relieve some of the workload of the "Abbotts & Hintons", letting
> them treat the stuff we can't.
> with sympathy
> >> Show that
> >> (df/dx)^2 + (df/dy)^2 =
> >Hi, it can't be shown because with
> >one gets for
> >(-4*(Cos[x]^2*Cos[y] + Sin[x]*Sin[y]^2))/(Cos[y] - Sin[x])^3
> >what is clearly different from Your "result"
> >Hope that helps
> > Jens
> NV Vandemoortele Coordination Center
> Oils & Fats Applied Research
> Prins Albertlaan 79
> Postbus 40
> B-8870 Izegem (Belgium)
> Tel: +/32/51/33 21 11
> Fax: +/32/51/33 21 75
Prev by Date:
fuctional differentiation in Mathematica
Next by Date:
Re: Bivariate Integrations/Assumptions error/
Prev by thread:
Re: How do u go about doing this---?
Next by thread:
Random Order of a Set of Numbers