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A Bug in Flatten?
Hi
This is Ted Ersek
I got the info on Flatten, and wanted to see what I can do when I give
it a third argument.
In[1]:=
Remove[f,g];
?Flatten
"Flatten[list] flattens out nested lists. Flatten[list, n] flattens to
level \
n. Flatten[list, n, h] flattens subexpressions with head h."
-------------------------------------- Examples:
In this case it looks like Flatten removed the two outer layers of (f)
In[2]:=
s1=g[f[f[f[1],f[2]],f[f[3],f[4]]]];
Flatten[s1,2,f]
Out[2]=
g[f[1],f[2],f[3],f[4]]
In this case all layers of (f) are removed. In[3]:=
Flatten[s1,Infinity,f]
Out[3]=
g[1,2,3,4]
In the next examples (f) doesn't appear until the third level. Now
Flatten doesn't see (f) at all. Should layers of (f) get removed in
these examples?
In[4]:=
s2=g[g[f[f[f[1],f[2]],f[f[3],f[4]]]]]; Flatten[s2,3,f]
Out[4]=
g[g[f[f[f[1],f[2]],f[f[3],f[4]]]]]
In[5]:=
Flatten[s2,Infinity,f]
Out[5]=
g[g[f[f[f[1],f[2]],f[f[3],f[4]]]]]
Ted Ersek
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