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MathGroup Archive 1998

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Re: "UnFullForm"ing an Expression?

  • To: mathgroup at
  • Subject: [mg13260] Re: [mg13151] "UnFullForm"ing an Expression?
  • From: Wouter Meeussen <eu000949 at>
  • Date: Fri, 17 Jul 1998 03:17:52 -0400
  • Sender: owner-wri-mathgroup at

hi Siegman,

my interpretation is:
you used SetDelayed or ":=" in defining f2 this stores:
f2[a_, x_] := D[f1[a, x], x]

when you put f2 in a table, and pass numeric values num1 and num2 values
for a and x, then this is substituded in the RHS of the definition,
resulting in : D[f1[num1, num2], num2] , causing your CPU to ache

curcumvent it with "Evaluate" :
In[13]:= Evaluate at f2[a,x]
Out[13]=a^2*Cos[x] - a*Sin[x]
and so:
Table[ Evaluate at f2[a,x],{x,3},{a,3}]

or else use a simple "Set" in the definition of f2.


At 07:42 13-07-98 -0400, AES wrote:
>I recently posted a query noting that if you enter the following
>   f1[a_,x_] :=a Cos[x] + a^2 Sin[x]
>   f2[a_,x_] := D[f1[a,x],x]
>you can make a Table[ ] of f1[a,x] but not of f2[a,x].  
>If I look at the FullForms for these, e.g.
>   f1[a,x] //  FullForm
>   f2[a,x] // FullForm
>they both look like simple functions to me (i.e., f2[a,x] shows no
>visible memory of having originated from a derivative), except the f2
>is inside a "FullForm[ ]" wrapper and f1 isn't.
>Is there a way to "UnFillForm" f2 ? If so, would f2 from then on act
>like f1 ?  Does this query make any sense?
>I'd like to understand the situation here.
>Thanks   siegman at
Dr. Wouter L. J. MEEUSSEN
w.meeussen.vdmcc at
eu000949 at

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