Re: (a-b)/(c-d)=!=(b-a)/(d-c) ???
- To: mathgroup at smc.vnet.net
- Subject: [mg13012] Re: (a-b)/(c-d)=!=(b-a)/(d-c) ???
- From: "Le Van Tri" <lvtri at cs.uwm.edu>
- Date: Tue, 30 Jun 1998 00:26:09 -0400
- Organization: University of Wisconsin - Milwaukee
- References: <6n4oke$nj7@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
This could fix for you: Unprotect[Simplify]; Simplify[Equal[x_,y_]]/;(y=!=0):=Equal[Simplify[x-y],0]; Unprotect[TrueQ]; TrueQ[x_]/;(Head[x]=!=Simplify):=If[Simplify[x],True,False]; Tim Dellinger wrote in message <6n4oke$nj7 at smc.vnet.net>... >How come >(a-b)/(c-d) === (b-a)/(d-c) > >returns False, i.e. TrueQ[ (a-b)/(c-d) =!= (b-a)/(d-c) ] returns True, > >but > >(a-b)/(c-d) === Simplify[ (b-a)/(d-c) ] > >returns True ??? > >Why does mere simplification change anything? I'm using Mathematica >3.0.? on win95. > > >-- >-- >"Perhaps my most deeply rooted hobby is to understand Tim >Dellinger > the mechanisms of simple and familiar >tdelling at uiuc.edu > natural phenomena." Irving Langmuir >http://www.ews.uiuc.edu/~tdelling >