       Re: (a-b)/(c-d)=!=(b-a)/(d-c) ???

• To: mathgroup at smc.vnet.net
• Subject: [mg13009] Re: [mg12964] (a-b)/(c-d)=!=(b-a)/(d-c) ???
• From: BobHanlon at aol.com
• Date: Tue, 30 Jun 1998 00:26:06 -0400
• Sender: owner-wri-mathgroup at wolfram.com

```Because === asks whether they are literally identical, not just equal
(see on- line Help for SameQ).  Before you apply Simplify to the rhs,
they are not literally identical; whereas, after you apply Simplify to
the rhs, they are.

You could also use

(a-b)/(c-d) == (b-a)/(d-c) // Simplify

Bob Hanlon

In a message dated 6/28/98 6:32:16 AM, tdelling at ews.uiuc.edu wrote:

>How come
>(a-b)/(c-d) === (b-a)/(d-c)
>
>returns False, i.e. TrueQ[ (a-b)/(c-d) =!= (b-a)/(d-c) ]  returns True,
>
>but
>
>(a-b)/(c-d) === Simplify[ (b-a)/(d-c) ]
>
>returns True ???
>
>Why does mere simplification change anything? I'm using Mathematica
>3.0.?  on win95.

```

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