Re: Find limit of series using Mathematica 2.0
- To: mathgroup@smc.vnet.net
- Subject: [mg12456] Re: [mg12393] Find limit of series using Mathematica 2.0
- From: Sean Ross <seanross@worldnet.att.net>
- Date: Tue, 19 May 1998 13:31:25 -0400
- References: <199805141515.LAA03821@smc.vnet.net.>
Cheung Wai Yuen wrote:
>
> I am a user of Mathematica 2.0. I do not know how to find the limit of
> series like :
> 1+ 1/2 + 1/4 + 1/16 + ..... . Please tell me the commands in doing so.
Simplify[Sum[1/2^n,{n,1,Infinity}]]
returns
1
I have used this same syntax for other series as well. One other
example is a partial sum of a geometric progression:
Simplify[Sum[a^n,{n,1,N}]]
returns
a (a^N-1)/(a-1).
I hope that this works in Mathematica 2.0. I use version 3.0.1. If you
have the funds, I recommend the upgrade.
- References:
- Find limit of series using Mathematica 2.0
- From: Cheung Wai Yuen <cwy1@netvigator.com>
- Find limit of series using Mathematica 2.0