Re: defining "regions"

*To*: mathgroup at smc.vnet.net*Subject*: [mg14770] Re: defining "regions"*From*: "M. Rommel" <rommel at bc.edu>*Date*: Sat, 14 Nov 1998 03:08:01 -0500*Organization*: UltraNet Communications , an RCN Company http://www.ultranet.com/*References*: <72588n$8an@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

I am sure it is not the most beautiful solution (it reflects my current level of expertise): In[18]:= pts={{1,2},{3,4},{1,5}}; In[19]:= F=(Abs[#[[1]]]<Pi/2)&&(Abs[#[[2]]]<Pi)&; In[20]:= F[{1,3}] Out[20]= True In[17]:= F/@pts Out[17]= {True,False,False} Let me know when you find a more elegant solution! Cheers, Martin Naum Phleger wrote in message <72588n$8an at smc.vnet.net>... > I have a discreet set of {x,y} points and I want to check if each is >in a particular continuos set of {x,y} points. I can only define the >region parametrically but other then that it looks something like this > >region= {-1<x<1 , 0<y<2} > >I want to perform a test like > >{x,y} "included in" region > >{0,1} "included in" region > ->True > >{5,7} "included in" region > ->False > > Is this possible My region is defined in a more difficult manner. >It looks more like this > > >region = F[{theta,fi}] for {-pi/2 < theta < pi/2}, {-pi < fi < pi } > >where F returns an {x,y} pair > > -NAUM >