Re: how to replace a list of variables

*To*: mathgroup at smc.vnet.net*Subject*: [mg14046] Re: [mg14017] how to replace a list of variables*From*: BobHanlon at aol.com*Date*: Fri, 18 Sep 1998 03:50:29 -0400*Sender*: owner-wri-mathgroup at wolfram.com

Works on my machine. Clear[x, y]; FindRoot[{x+y == 10, x == y}, {x, 3}, {y, 3}] {x,y}={x,y}/.% {5., 5.} Clear[x, y]; FindRoot[{E^(x+y) == 10, x == y+2}, {x, 3}, {y, 3}] {x,y}={x,y}/.% {2.15129254649721, 0.1512925464972104} If you had previously made an assignment to x or y and didn't clear the assignment, you might get a bad result. For example, FindRoot[{x+y == 10, x == y}, {x, 3}, {y, 3}] {x,y}={x,y}/.% {5., 5.} FindRoot[{E^(x+y) == 10, x == y+2}, {x, 3}, {y, 3}] {x,y}={x,y}/.% {2.15129254649721, 2.15129254649721} Bob Hanlon In a message dated 9/16/98 4:56:19 PM, wus at econ.lsa.umich.edu wrote: >Hi, I just got emails discussing how to assign a solution to a variable. >However, the same approach doesn't work for the following similar >question, in which the solution is a vector. > >FindRoot[{x+y==10,x==y},{x,3},{y,3}] {{x->5,y->5}} >{x,y}={x,y}/.%