Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
1998
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 1998

[Date Index] [Thread Index] [Author Index]

Search the Archive

A very difficult equation ...

  • To: mathgroup at smc.vnet.net
  • Subject: [mg14063] A very difficult equation ...
  • From: tobi.kamke at t-online.de (Julia Kamke)
  • Date: Sat, 19 Sep 1998 03:41:59 -0400
  • Sender: owner-wri-mathgroup at wolfram.com

Hi!!!


f[x_] := -2 + 2 * Cos[x] + x * Sin[x]

How can I solve the equation f[x] == 0 in a symbolic way? Solve[f[x] ==
0, x] says, that it isn't possible to solve this equation! Furthermore
I can't simplify this equation. But I think, that x = z * 2 * Pi (z =
.. -2, -1, 0, 1, 2 ...) are some of the possible solutions. Is there a
trick or a possibility to find out this solutions and the rest of all
solutions with Mathematica??

Please help me!!!


Thanks,

  Tobi


P. S. Is f[x] == Sin[x](Sin[x](x^2 + 4) - 4x)??? How can I find this out
with Mathematica??



  • Prev by Date: Help with evaluation of infinite summation
  • Next by Date: Re: Font problems on X-Windows
  • Previous by thread: Re: Help with evaluation of infinite summation
  • Next by thread: Re: A very difficult equation ...