RE: Sqrt problems

• To: mathgroup at smc.vnet.net
• Subject: [mg19522] RE: [mg19504] Sqrt problems
• From: "Ersek, Ted R" <ErsekTR at navair.navy.mil>
• Date: Sun, 29 Aug 1999 03:00:40 -0400
• Sender: owner-wri-mathgroup at wolfram.com

```Rita Bijlsma wrote:
------------------------
I'm working with the textual version of mathematica 2.2 on VMS and I have
some questions related to Sqrt

PowerExpand[%15]

2   2            4    4   4
1   n  Pi    Sqrt[4 Dq  + n  Pi ]
- - ------ + --------------------
2       2               2
4 Dq            4 Dq

- How do I get mathematica to give me:

2   2             4   4
1   n  Pi         1   n  Pi
- - ------ + Sqrt[- + ------]
2       2         4        4
4 Dq              16 Dq

<snip>
(* and several other broad questions. *)

-------------------------------

The following should help with one of your problems.

In[1]:=
1/2 - (n^2*Pi^2)/(4*Dq^2) + Sqrt[4*Dq^4 + n^4 + Pi]/(4*Dg^2)/. a_
Sqrt[b_]:>Sqrt[a^2 *b]

Out[1]=
1/2 - (n^2*Pi^2)/(4*Dq^2) + Sqrt[(4*Dq^4 + n^4 + Pi)/Dg^4]/4

This pattern matching stuff takes some practice before you get good at it.
I have a section on Pattern matching on the web page I mention below.  You

--------------------
Regards,
Ted Ersek

For Mathematica tips, tricks see
http://www.dot.net.au/~elisha/ersek/Tricks.html

```

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