Re: Help! How to execute line integral, surface integral or integration around contour.
- To: mathgroup at smc.vnet.net
- Subject: [mg21089] Re: Help! How to execute line integral, surface integral or integration around contour.
- From: "Stephen P Luttrell" <luttrell at signal.dra.hmg.gb>
- Date: Sun, 12 Dec 1999 23:51:57 -0500 (EST)
- Organization: Defence Evaluation and Research Agency
- References: <7hgdpv$4ck@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Kazuhiko Kato <kato at cam.hi-ho.ne.jp> wrote in message news:7hgdpv$4ck at smc.vnet.net... > > Please teach me how to execute line integral, surface integral or > integration of analytic function around a contour by using mathematica Is this the sort of thing you are looking for? In[1]:=Integrate[1/z,{z,1,I,-1,-I,1}] Out[1]=2 I \[Pi] The {z,1,I,-1,-I,1} specifies a diamond-shaped contour in the complex z plane that encloses the pole in 1/z at the origin. -- Stephen P Luttrell Signal Processing and Imagery Department DERA Malvern, St.Andrew's Road Malvern, United Kingdom, WR14 3PS +44 (0)1684 894046 (tel) +44 (0)1684 894384 (fax) luttrell at signal.dera.gov.uk (email)