Re: REDUCE vs. a symoblic function
- To: mathgroup at smc.vnet.net
- Subject: [mg18273] Re: REDUCE vs. a symoblic function
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Fri, 25 Jun 1999 15:05:20 -0400
- Organization: Universitaet Leipzig
- References: <firstname.lastname@example.org>
- Sender: owner-wri-mathgroup at wolfram.com
Mathematica should get the same result in all 4 cases ? Realy ?
I get in the last two cases for F==Sin or F==Cos
q== 2Pi n and any a and any interger n,
but that is not a solution for the first two.
Can you explain why the result for any F should be
the same ?
> When I type in:
> Reduce[a*q - a ==0,a}
> Reduce[a*q - a ==0,q]
> I get the result: a == 0 OR q == 1
> However, if I type in:
> Reduce[ F[a*q] - F[a] == 0,a] I just get back Reduce[
> F[a*q] - F[a] == 0,a]
> and if I type in:
> Reduce[ F[a*q] - F[a] == 0,q] I get back
> a NOT == 0 && q == 1
> Why the difference in these outcomes? These questions were,
> in part, motivated by the statement "As well as treating variables like x
> symbolically, you can also treat functions , like f[x], in Mathematica
> symbolically.....without specifying any explicit form for the function
> f[x]." Secondly, assuming that Mathematica doesnt get the result rather
> then I didnt use the correct commands to get them, and even if you can
> explain why it didnt, should it have gotten the same result in all 4 cases?
> Thanks. Jerry Blimbaum NSWC Panama City, Fl
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