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Re: M.U.C.

  • To: mathgroup at smc.vnet.net
  • Subject: [mg20611] Re: M.U.C.
  • From: "Allan Hayes" <hay at haystack.demon.co.uk>
  • Date: Thu, 4 Nov 1999 02:13:28 -0500
  • References: <7vm3io$q82@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Roscoe:

SolveAlways[E^(-2 x)((-3) + 10 b - x + 6 a(1 + 5 x)) == 0, {x}]

    {{a -> 1/30, b -> 7/25}}

Allan
---------------------
Allan Hayes
Mathematica Training and Consulting
Leicester UK
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565


Roscoe <roscoe at hazardcounty.org> wrote in message
news:7vm3io$q82 at smc.vnet.net...
> How can Mathematica solve the following Linear Operator for a and b?
> (E^(-2 x)((-3) + 10 b - x + 6 a(1 + 5 x)) == 0
>
> By hand it would be :
> (-3+10b+6a)=0
> (-1+30a)=0
>
> a=1/30
> b=whatever
>
> I need mathematica to group the coeeficients of x^0 and x^1, set them
equal
> to 0 and solve.
> I am trying to avoid doing the gruoping by hand.  Thanks.
>
>
>



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