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Re: F[f_,x_]:=f[x] ?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg20155] Re: [mg19819] F[f_,x_]:=f[x] ?
  • From: "Neal E. Tornberg" <neal.e.tornberg at boeing.com>
  • Date: Sat, 2 Oct 1999 03:05:10 -0400
  • Organization: Boeing
  • References: <7sv0d2$23k@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Compose has been superceded by Composition

Daniel Reeves wrote:
> 
> I just stumbled upon the built-in but undocumented function Compose, which
> apparently does exactly that.
> Comments from Wolfram developers...?
> (probably a better functionality for Compose would be the last element of
> ComposeList, to be consistent with Nest and Fold)
> 
> ----- FROM Patrick McLean ON 99.09.17 01:37 (Sep 17) -----
> 
> > What is the name of the in-built Mathematica function that plays the role
> > of F in te following:
> >
> > F[f_,x_]:=f[x].
> >
> > For example,
> >
> > Outer[F,{f,g},{x,y}]
> >
> > will give:
> >
> > {{f[x],f[y]},{g[x],g[y]}}.
> >
> > --
> > Patrick McLean
> >
> > No news is good news...
> >
> 
> --    --    --    --    --    --    --    --    --    --    --    --
> Daniel Reeves               http://ai.eecs.umich.edu/people/dreeves/
> 
> "If at first you don't succeed -- try, try again.
> Then quit.  No use being a damn fool about it."

-- 
Neal E. Tornberg
neal.e.tornberg at boeing.com

Nobody here thinks I speak for Boeing.
You shouldn't either.



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