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Re: Re: F[f_,x_]:=f[x] ?


This might have unintended consequences, e.g.:

In[1]:=
Outer[MapAll, {f, g}, {x[1], y[1]}]
Out[1]=
{{f[x[f[1]]], f[y[f[1]]]}, {g[x[g[1]]], g[y[g[1]]]}}

while

In[2]:=
Outer[#1[#2] &, {f, g}, {x[1], y[1]}]
Out[2]=
{{f[x[1]], f[y[1]]}, {g[x[1]], g[y[1]]}}
--
Andrzej Kozlowski
Toyama International University
JAPAN
http://sigma.tuins.ac.jp
http://eri2.tuins.ac.jp


----------
>From: BobHanlon at aol.com
To: mathgroup at smc.vnet.net
>To: mathgroup at smc.vnet.net
>Subject: [mg19881] [mg19873] Re: [mg19819] F[f_,x_]:=f[x] ?
>Date: Sun, 19 Sep 1999 01:20:55 -0400
>

> Patrick,
>
> MapAll seems to work:
>
> MapAll[f, x]
>
> f[x]
>
> Outer[MapAll, {f, g}, {x, y}]
>
> {{f[x], f[y]}, {g[x], g[y]}}
>
> Bob Hanlon
>
> In a message dated 9/17/1999 10:58:23 AM, p_mclean at postoffice.utas.edu.au
> writes:
>
>>What is the name of the in-built Mathematica function that plays the role
>>of F in te following:
>>
>>F[f_,x_]:=f[x].
>>
>>For example,
>>
>>Outer[F,{f,g},{x,y}]
>>
>>will give:
>>
>>{{f[x],f[y]},{g[x],g[y]}}.
>>
> 


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