Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
1999
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 1999

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Re: Re: Re: Mathematica can't win against Tiger Woods

  • To: mathgroup at smc.vnet.net
  • Subject: [mg19888] Re: [mg19877] Re: [mg19811] Re: [mg19765] Re: [mg19677] Mathematica can't win against Tiger Woods
  • From: "Andrzej Kozlowski" <andrzej at tuins.ac.jp>
  • Date: Sun, 19 Sep 1999 18:47:36 -0400
  • Sender: owner-wri-mathgroup at wolfram.com

This is indeed mysterious and somewhat worrying but still one can deal with
it (though admittedly one would not want to have to do this sort of thing
very often):

In[78]:=
FullSimplify[(Sqrt[2] x/2)^2 Sin[x/2]^2,
  ComplexityFunction -> (Count[{#}, _Sin, Infinity] &)]

Out[78]=
  1   2
-(-) x  (-1 + Cos[x])
  4
--
Andrzej Kozlowski
Toyama International University
JAPAN
http://sigma.tuins.ac.jp
http://eri2.tuins.ac.jp


----------
>From: Leszek Sczaniecki <leszek2 at home.com>
>To: mathgroup at smc.vnet.net
>Subject: [mg19888] [mg19877] Re: [mg19811] Re: [mg19765] Re: [mg19677] Mathematica can't win against Tiger Woods
>Date: Sun, Sep 19, 1999, 2:20 PM
>

> Or perhaps, for what
> technical reason it can do this simplification
>
> In[1]:= FullSimplify[(Sqrt[2] 1/2))^2 Sin[x/2]^2]
>
> Out[1]=
> 1/4 (1 - Cos[x])
>
> but fails here
>
> In[2]:= FullSimplify[(Sqrt[2] x/2))^2 Sin[x/2]^2]
>
> Out[2]=
> 1/2 x^2 Sin[x/2]^2
> ?


  • Prev by Date: Re: F[f_,x_]:=f[x] ?
  • Next by Date: Re: Bode-Diagrams
  • Previous by thread: Re: Re: Mathematica can't win against Tiger Woods
  • Next by thread: Version 3 vs Version 4