       Re: Out=((5-Sqrt)/20 + (5+Sqrt)/20 ) == 1/2 ???

• To: mathgroup at smc.vnet.net
• Subject: [mg20007] Re: Out=((5-Sqrt)/20 + (5+Sqrt)/20 ) == 1/2 ???
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Sat, 25 Sep 1999 02:40:38 -0400
• Organization: Universitaet Leipzig
• References: <7se6fk\$qsc@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```H Patrick,

you ask is ( (5-Sqrt)/20 + (5+Sqrt)/20 )

equal to 1/2. This should be True. To evaluate this Mathematica
don't call Together[]. It find that

NumericQ[( (5-Sqrt)/20 + (5+Sqrt)/20 ) ]

yield True and try to evaluate it numerical :-(

This gives the message from the numerical evaluation.

Hope that helps
Jens

Patrick McLean wrote:
>
> Can any one explain this behaviour???
>
>
> In:=   ( (5-Sqrt)/20 + (5+Sqrt)/20 ) == 1/2
>
> \$MaxExtraPrecision::meprec:
>    \$MaxExtraPrecision = 50. reached while evaluating
>       1    5 - Sqrt   5 + Sqrt
>     -(-) + ----------- + -----------. Increasing the value of
>       2        20            20
>      \$MaxExtraPrecision may help resolve the uncertainty.
>
>         5 - Sqrt   5 + Sqrt    1
> Out= ----------- + ----------- == -
>             20            20         2

> Patrick McLean
>
> No news is good news...

```

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