Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
1999
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 1999

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Out[1]=((5-Sqrt[5])/20 + (5+Sqrt[5])/20 ) == 1/2 ???

  • To: mathgroup at smc.vnet.net
  • Subject: [mg20013] Re: Out[1]=((5-Sqrt[5])/20 + (5+Sqrt[5])/20 ) == 1/2 ???
  • From: "Kevin J. McCann" <kevin.mccann at jhuapl.edu>
  • Date: Sat, 25 Sep 1999 02:40:42 -0400
  • Organization: Johns Hopkins University Applied Physics Lab, Laurel, MD, USA
  • References: <7se6fk$qsc@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Indeed, it does seem a bit strange, especially since

In[1]:= Simplify[( (5-Sqrt[5])/20 + (5+Sqrt[5])/20 ) ]

Out[1]:=  1/2

--

Kevin J. McCann
Johns Hopkins University APL

Patrick McLean <p_mclean at postoffice.utas.edu.au> wrote in message
news:7se6fk$qsc at smc.vnet.net...
> Can any one explain this behaviour???
>
> hilbert% math
> Mathematica 3.0 for Solaris
> Copyright 1988-96 Wolfram Research, Inc.
>  -- Terminal graphics initialized --
>
> In[1]:=   ( (5-Sqrt[5])/20 + (5+Sqrt[5])/20 ) == 1/2
>
> $MaxExtraPrecision::meprec:
>    $MaxExtraPrecision = 50. reached while evaluating
>       1    5 - Sqrt[5]   5 + Sqrt[5]
>     -(-) + ----------- + -----------. Increasing the value of
>       2        20            20
>      $MaxExtraPrecision may help resolve the uncertainty.
>
>         5 - Sqrt[5]   5 + Sqrt[5]    1
> Out[1]= ----------- + ----------- == -
>             20            20         2
>
> In[2]:=
>
> --
> Patrick McLean
>
> No news is good news...
>




  • Prev by Date: Re: How to make Package?
  • Next by Date: Re: Enumerating Permutations
  • Previous by thread: Re: Out[1]=((5-Sqrt[5])/20 + (5+Sqrt[5])/20 ) == 1/2 ???
  • Next by thread: Re: Out[1]=((5-Sqrt[5])/20 + (5+Sqrt[5])/20 ) == 1/2 ???