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MathGroup Archive 2000

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Programming Help. PLEASE (2)

  • To: mathgroup at smc.vnet.net
  • Subject: [mg22986] Programming Help. PLEASE (2)
  • From: gemilord at blue.seas.upenn.edu (Geoffrey B Milord)
  • Date: Sun, 9 Apr 2000 01:45:51 -0400 (EDT)
  • Organization: University of Pennsylvania
  • Sender: owner-wri-mathgroup at wolfram.com

Why does the following routine Milord[1,3] work but not Milord[2,3]?
I am not familiar with Mathematica but I stepped through it. The problem seems 
to be with the assignment of t1 in the last line of the for loop.

When you post mail me as well.
Thanks.

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Cell[CellGroupData[{
Cell[BoxData[
    \(\(\(\[IndentingNewLine]\)\(F = \ 
      BitOr[BitAnd[#1, #2], BitAnd[BitNot[#1], #3]] &\)\)\)], "Input"],

Cell[BoxData[
    \(BitOr[BitAnd[#1, #2], BitAnd[BitNot[#1], #3]] &\)], "Output"]
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Cell[BoxData[
    \(\[IndentingNewLine]\)], "Input"],

Cell[BoxData[
    \(\(\(\[IndentingNewLine]\)\(\(Milord[numSteps_, 
        start_]\)\(:=\)\(Module[{t0, 
          t1}, \ \[IndentingNewLine]t0\  = {}; \t\[IndentingNewLine]t0\  = 
          Append[t0, 
            Table[Random[Integer], {128}]]; \[IndentingNewLine]t1\  = 
          t0[\([1]\)]; \[IndentingNewLine]t1\  = \ 
          RotateRight[t1, Mod[\(-start\), 4]*32]; \[IndentingNewLine]For\ [
          i = 0, i < numSteps, \(i++\), \[IndentingNewLine]\ 
          t1\  = Join[
              Table[F[t1[\([j + 32]\)], t1[\([j + 64]\)], 
                  t1[\([j + 96]\)]], {j, 32}], 
              Table[t1[\([j]\)], {j, 33, 128}]]; \[IndentingNewLine]t0 = \ 
            Append[t0, \ 
              RotateRight[
                t1, \(-Mod[i - start, 4]\)*32]]; \[IndentingNewLine]t1\  = 
            R\ otateRight[t1, 32]]; \[IndentingNewLine]\t
        Return[t0]]\)\(\[IndentingNewLine]\)\(\[IndentingNewLine]\)\(\
\[IndentingNewLine]\)\)\)\)], "Input"]
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