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RE: Clear or remove definitions including Subscripts

  • To: mathgroup at smc.vnet.net
  • Subject: [mg23154] RE: [mg23116] Clear or remove definitions including Subscripts
  • From: "David Park" <djmp at earthlink.net>
  • Date: Thu, 20 Apr 2000 03:21:22 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

> From: SANCHEZ DE LEON, Guillermo [mailto:gsl at fab.enusa.es]
To: mathgroup at smc.vnet.net
> Dear friends,
>
> If I write:
>
> In[1]:= Subscript[a, 11];
> In[2]:= Subscript[a, 12];
>
> Q1: How I can Clear or Remove the previous definitions?.
> Q2: Is it posible to clear at the same time all definitions with pattern:
> Subscript[a, i] (* i=1,2,..*)
>
> I wish to avoid using Notation Package
>
> I have tested:
>
> In[3]: Clear[Subscript[a, 11]]
> Message: Clear:: "ssym": a_11 is not a symbol or a string
>
> In[4]: Clear["\!\(a\_11\)"]
>
> But they don`t work
>

Here is a Mathematica notebook, which if you open and save, will produce a
package called WollSubscripts. I wrote the package as a slight modification
and extension of a suggestion first put forward by Carl Woll in MathGroup.
It allows you to use subscripted symbols, even if the subscript has been
given a value elsewhere. It also has routines for clearing the subscript
variables and obtaining information on them. The package should be put in
the AddOns/ExtraPackages/Algebra directory.

Copy the text and paste it into an empty notebook.

David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/



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Cell[CellGroupData[{

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Cell[BoxData[{
    \(ClearAll[Subscript]\), "\[IndentingNewLine]",
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HoldFirst so that it can be used like a symbol and be given \
definitions.\>";\)\), "\[IndentingNewLine]",
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definitions can be defined. The additional routines ClearSubscripts and \
SubscriptInformation are also provided.\>"\)], "Input",
  InitializationCell->True],

Cell[BoxData[
    \(\(ClearSubscripts::usage = "\<ClearSubscripts[sym1, sym2,...] will \
clear all Subscript definitions based on the symbols.\>";\)\)], "Input",
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    \(\(SubscriptInformation::usage = "\<SubscriptInformation[sym1,
sym2,...] \
will print the Subscript definitions based on the symbols.\>";\)\)],
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  InitializationCell->True],

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    \(Begin["\<`Private`\>"]\)], "Input",
  InitializationCell->True],

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      Module[{b}, \[IndentingNewLine]DownValues[Subscript]\  =
          Cases[DownValues[Subscript], \((b_\  :> \ _)\)\  /; \
              FreeQ[b,
                HoldPattern[
                  Subscript[
                    Alternatives[a], \ __]]]]; \[IndentingNewLine]SubValues[
            Subscript]\  =
          Cases[SubValues[Subscript], \((b_\  :> \ _)\)\  /; \
              FreeQ[b,
                HoldPattern[
                  Subscript[
                    Alternatives[
                      a], \ __]]]];\[IndentingNewLine]]\)}], "Input",
  InitializationCell->True],

Cell[BoxData[{
    StyleBox[\(SetAttributes[SubscriptInformation, \ {HoldAll}];\),
      FormatType->StandardForm], "\n",
    StyleBox[\(SubscriptInformation[syms__]\  := \[IndentingNewLine]\
        Module[{PrintDownValue},
\[IndentingNewLine]PrintDownValue[\(Verbatim[
                    HoldPattern]\)[a_]\  :> \ b_]\  := \
            Print[HoldForm[
                a\  = \
                  b]]; \[IndentingNewLine]PrintDownValue\  /@
\((DeleteCases[
                Join[DownValues[Subscript],
                  SubValues[Subscript]], \ \((b_\  :> \ _)\)\  /; \
                  FreeQ[b,
                    HoldPattern[
                      Subscript[
                        Alternatives[
                          syms], \ __]]]])\);\[IndentingNewLine]]\),
      FormatType->StandardForm]}], "Input",
  InitializationCell->True],

Cell[BoxData[
    \(End[]\)], "Input",
  InitializationCell->True],

Cell[BoxData[
    \(Protect[ClearSubscripts, SubscriptInformation]\)], "Input",
  InitializationCell->True],

Cell[BoxData[
    \(EndPackage[]\)], "Input",
  InitializationCell->True]
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