Re: Integrating Conditionals/piecewise cont. functions

• To: mathgroup at smc.vnet.net
• Subject: [mg26227] Re: Integrating Conditionals/piecewise cont. functions
• From: "Richard Lindenberg" <georgepburdell at hotmail.com>
• Date: Wed, 6 Dec 2000 02:16:15 -0500 (EST)
• Organization: University of Illinois at Urbana-Champaign
• References: <90ejrq\$lp9@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```I think that I found the answer to my question. I simply multiply any
function I want times a UnitStep function at that interval.

I am still taking suggestions though...

Rich Lindenberg

"Richard Lindenberg" <georgepburdell at hotmail.com> wrote in message
news:90ejrq\$lp9 at smc.vnet.net...
> I am trying to do some simplified finite elements that simply requires the
> integration of some roof functions (i.e. piecewise continous functions
that
> are 0 everywhere except where they ramp up and then down in a specified
> domain). I was hoping that I could do everything symbolically, but
> Mathemtica refuses to integrate every conditional I give it. I can get it
to
> do the numerically, but it comes with baggage. This is what I have right
> now:
>
> These are roof functions differentiated
>
> Piecewise continuous
> b'[x_, n_] :=
>   Which[x < n, 0, n <= x <= n + 1, 1, n + 1 < x < n + 2, -1, x >= n + 2,
0]
>
> Another way to look at it
> v'[x_, n_] := 0 /; x < n
> v'[x_, n_] := 1 /; n <= x <= n + 1
> v'[x_, n_] := -1 /; n + 1 < x < n + 2
> v'[x_, n_] := 0 /; x >= n + 2
>
> I want to simply do this...
>
> Integrate[v'[x,m] v'[x,n]]  for m=n=1...5 (or something)
>
> (If you copy the below item into Mathematica you will see exactly, I
> think...)
>
> Essentially I am trying to make a matrix full of the these functions. The
> numerical integrate seems to work, but keeps spitting up after trying to
> integrate integrands of zero. I suppose if I could turn this off that
would
> be good. The other stuff in the table function just makes it a
tridiagonal.
>
> \!\(Table[
>     Switch[i - j, \(-1\),
>       N[\[Integral]\_0\%5\((\(v'\)[x, i]\ \(v'\)[x, j])\)
> \[DifferentialD]x],
>       0, N[\[Integral]\_0\%5\((\(v'\)[x, i]\ \(v'\)[x,
>                   j])\) \[DifferentialD]x], 1,
>       N[\[Integral]\_0\%5\((\(v'\)[x, i]\ \(v'\)[x,
>                   j])\) \[DifferentialD]x], _, 0], {i, 5}, {j, 5}]\)
>
> Appreciate any help/ideas...
>
> Thanks,
> Rich Lindenberg
> UIUC
>
>

```

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