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Re: ListContourPlot3D

  • To: mathgroup at
  • Subject: [mg26264] Re: ListContourPlot3D
  • From: Jens-Peer Kuska <kuska at>
  • Date: Sun, 10 Dec 2000 00:19:38 -0500 (EST)
  • Organization: Universitaet Leipzig
  • References: <90kroh$>
  • Sender: owner-wri-mathgroup at


1.  Just set EdgeForm[] in the ContourStyle option
2.  you must generate a 3d interpolation and make a 
    ContourPlot3D[] on the interpolation

You may look at

the OpenGL Viewer has now a buil-in iso-surface command
with interactive adjustment of the level. Clearly
MathGL3d is much faster computing 3d contour surfaces,
50000 polygons/second can be found and rendered with
MathGL3d. It has an automatic polygon reduction that
will also create nice triangulations for fine resolved
data and functions.


David Djajaputra wrote:
> Hello,
> I'm using ListContourPlot3D to generate a surface based on numerical
> data points on an 8x8x8 cubic grid.
> 1. Is it possible to remove the lines drawn on the surface so that I
> have just a nice surface?
> 2. Is it possible to "smooth" this surface using some kind of smooth
> interpolation in Mathematica? Or do I really have to compute my data
> points on a finer grid to get a smoother surface? The surface that I'm
> dealing with is pretty much well behaved and slowly varying.
> Any pointer on how to do this smoothing business in Mathematica will be
> greatly appreciated.
> Thanks!
> David

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