Re: ListContourPlot3D
- To: mathgroup at smc.vnet.net
- Subject: [mg26264] Re: ListContourPlot3D
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Sun, 10 Dec 2000 00:19:38 -0500 (EST)
- Organization: Universitaet Leipzig
- References: <90kroh$r5m@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hi,
1. Just set EdgeForm[] in the ContourStyle option
2. you must generate a 3d interpolation and make a
ContourPlot3D[] on the interpolation
You may look at
http://phong.informatik.uni-leipzig.de/~kuska/mathgl3dv3
the OpenGL Viewer has now a buil-in iso-surface command
with interactive adjustment of the level. Clearly
MathGL3d is much faster computing 3d contour surfaces,
50000 polygons/second can be found and rendered with
MathGL3d. It has an automatic polygon reduction that
will also create nice triangulations for fine resolved
data and functions.
Regards
Jens
David Djajaputra wrote:
>
> Hello,
>
> I'm using ListContourPlot3D to generate a surface based on numerical
> data points on an 8x8x8 cubic grid.
>
> 1. Is it possible to remove the lines drawn on the surface so that I
> have just a nice surface?
>
> 2. Is it possible to "smooth" this surface using some kind of smooth
> interpolation in Mathematica? Or do I really have to compute my data
> points on a finer grid to get a smoother surface? The surface that I'm
> dealing with is pretty much well behaved and slowly varying.
>
> Any pointer on how to do this smoothing business in Mathematica will be
> greatly appreciated.
>
> Thanks!
>
> David