Re: transposing an equation

*To*: mathgroup at smc.vnet.net*Subject*: [mg26294] Re: transposing an equation*From*: leko at ix.netcom.com (J. Leko)*Date*: Sun, 10 Dec 2000 00:20:04 -0500 (EST)*References*: <90kq3d$r25@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

You could do this: In[2]:= Solve[y == a x^2 + b x + c, x] Out[2]= \!\({{x -> \(\(-b\) + \ at \(b\^2 - 4\ a\ c + 4\ a\ y\)\)\/\(2\ a\)}, {x -> \ \(-\(\(b + \ at \(b\^2 - 4\ a\ c + 4\ a\ y\)\)\/\(2\ a\)\)\)}}\) (sorry about the formating). Although in this case, you get something similar to the quadratic equation for answers, so there are really no A, B, and C's. In article <90kq3d$r25 at smc.vnet.net>, "Christopher Deacon" <cdeacon at physics.mun.ca> wrote: > Suppose y=a x^2+b x +c. > > How can I get Mathematica to solve for x (i.e., x=Ay^2+By+C) and give me the > values for the constants A,B,C? > > Chris > > -- > +-----------------------------+----------------------------+ > | Christopher Deacon | (709) 737-7631 > | Dept of Physics and Physical| cdeacon at physics.mun.ca > | Oceanography > | Memorial University of Nfld > +----------------------------+-----------------------------+ > | http://www.physics.mun.ca/~cdeacon > +----------------------------------------------------------+ J. Leko Please e-mail replies to leko*j at cspar.uah.edu and remove the *