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RE: Bug in Limit Package


Joel,

With Version 4.0.1 I obtain:

lim = Limit[Erf[a, x], x -> Infinity]
1 - Erf[a]

lim /. a -> 1
1 - Erf[1]

lim /. a -> -1
1 + Erf[1]

which appears to be correct.

David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/ 

> From: Joel Storch [mailto:jstorch at earthlink.net]
To: mathgroup at smc.vnet.net
> If we attempt to compute
> 
> Limit[Erf[a x],x->Infinity]
> 
> Mathematica returns the result unevaluated. If the same command is
> issued after loading the package Calculus`Limit`, the value 1 is
> returned. Clearly, this is correct only if a >0 (for a < 0, the limit is
> 
> -1).
> 


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