Re: simple plot

*To*: mathgroup at smc.vnet.net*Subject*: [mg22389] Re: simple plot*From*: "Allan Hayes" <hay at haystack.demon.co.uk>*Date*: Sun, 27 Feb 2000 18:55:29 -0500 (EST)*References*: <89a592$9gp@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Steve, Load the Standard Package (see Help Browser) << Graphics`ContourPlot3D` Then ContourPlot3D[x^2 + y^2 - z^2, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}] gives the surface. Allan --------------------- Allan Hayes Mathematica Training and Consulting Leicester UK www.haystack.demon.co.uk hay at haystack.demon.co.uk Voice: +44 (0)116 271 4198 Fax: +44 (0)870 164 0565 "Steve" <sdunkel at ucsd.edu> wrote in message news:89a592$9gp at smc.vnet.net... > How do I plot the following function? > > x^2+y^2-z^2=0 > > I know this is a simple question but I'm new to Mathematica. > > Thanks > > >