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Re: Product with p!=j

guillerm at wrote:

> I have the following problem:
> q[n_]:= Sum[1/Product[Subscript[k, p] - Subscript[k, j], {p, 1, 
> n}], {j, 1, n}], with p!=j
> Any suggestions?.

Perhaps this will help:

d[p_, j_] := If[p != j, 1/(Subscript[k, p] - Subscript[k, j]), 1]

q[n_] = Sum[Product[d[p, j], {p, 1, n}], {j, 1, n}]

Tomas Garza
Mexico City

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