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Re: Why doesn't Log[ E^x ] = x ?
Because the Log, considered as a complex function, is multivalued. E.g. Log[E^2]=2 but Log[E^(2+2Pi I)]=2 that is Mathematica's answer, rather than (2+2Pi I) which is not on the principle branch. And Log[E^(I 2Pi)]=0 not I 2Pi When you try Log[E^x] Mathematica doesn't know enough about x to answer; so it doesn't. Kevin "Christopher R. Carlen" <crcarle at sandia.gov> wrote in message news:8jrdc2$e2t at smc.vnet.net... > Hi: > > E^Log[x] evaluates to x > > but > > Log[ E^x ] evaluates to Log[ E^x ] > > Why? > > Thanks. > > P.S. Mathematica 3.0 > > _______________________ > Christopher R. Carlen > Sr. Laser/Optical Tech. > Sandia National Labs >