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Re: l'Hopital's Rule

If you divide numerator and denominator by a, Mathematica will then give the
correct answer of 2a. Also if a is replaced by a number, the correct
answer is given. I would call this a bug in the Limit.


heathw at wrote:
> Hi,
> When I input this:
> Limit[(a^2 - a*x)/(a - Sqrt[a*x]), x -> a]
> The output is:
> 0
> The output should be 2*a.
> Can't Mathematica 4 use l'Hopital's Rule?
> Thanks,
> Heath

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