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Re: l'Hopital's Rule
- To: mathgroup at smc.vnet.net
- Subject: [mg24331] Re: l'Hopital's Rule
- From: "Kevin J. McCann" <Kevin.McCann at jhuapl.edu>
- Date: Sun, 9 Jul 2000 04:52:39 -0400 (EDT)
- Organization: Johns Hopkins University Applied Physics Lab, Laurel, MD, USA
- References: <8k3oi3$42k@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
If you divide numerator and denominator by a, Mathematica will then give the
correct answer of 2a. Also if a is replaced by a number, the correct
answer is given. I would call this a bug in the Limit.
Kevin
heathw at in-tch.com wrote:
>
> Hi,
> When I input this:
> Limit[(a^2 - a*x)/(a - Sqrt[a*x]), x -> a]
> The output is:
> 0
> The output should be 2*a.
> Can't Mathematica 4 use l'Hopital's Rule?
> Thanks,
> Heath
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