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MathGroup Archive 2000

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Re: l'Hopital's Rule

  • To: mathgroup at smc.vnet.net
  • Subject: [mg24331] Re: l'Hopital's Rule
  • From: "Kevin J. McCann" <Kevin.McCann at jhuapl.edu>
  • Date: Sun, 9 Jul 2000 04:52:39 -0400 (EDT)
  • Organization: Johns Hopkins University Applied Physics Lab, Laurel, MD, USA
  • References: <8k3oi3$42k@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

If you divide numerator and denominator by a, Mathematica will then give the
correct answer of 2a. Also if a is replaced by a number, the correct
answer is given. I would call this a bug in the Limit.

Kevin

heathw at in-tch.com wrote:
> 
> Hi,
> When I input this:
> Limit[(a^2 - a*x)/(a - Sqrt[a*x]), x -> a]
> The output is:
> 0
> The output should be 2*a.
> Can't Mathematica 4 use l'Hopital's Rule?
> Thanks,
> Heath


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