Re: l'Hopital's Rule

*To*: mathgroup at smc.vnet.net*Subject*: [mg24331] Re: l'Hopital's Rule*From*: "Kevin J. McCann" <Kevin.McCann at jhuapl.edu>*Date*: Sun, 9 Jul 2000 04:52:39 -0400 (EDT)*Organization*: Johns Hopkins University Applied Physics Lab, Laurel, MD, USA*References*: <8k3oi3$42k@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

If you divide numerator and denominator by a, Mathematica will then give the correct answer of 2a. Also if a is replaced by a number, the correct answer is given. I would call this a bug in the Limit. Kevin heathw at in-tch.com wrote: > > Hi, > When I input this: > Limit[(a^2 - a*x)/(a - Sqrt[a*x]), x -> a] > The output is: > 0 > The output should be 2*a. > Can't Mathematica 4 use l'Hopital's Rule? > Thanks, > Heath