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MathGroup Archive 2000

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Re: Pattern Matching

  • To: mathgroup at smc.vnet.net
  • Subject: [mg23847] Re: [mg23826] Pattern Matching
  • From: Andrzej Kozlowski <andrzej at tuins.ac.jp>
  • Date: Mon, 12 Jun 2000 01:17:37 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

The problem is that Plus[Times[x[_], b[_]] ..] evaluates before the pattern
matching is performed and Plus disappears from the Pattern (Plus[a] gives
a):

In[6]:=
Plus[Times[x[_], b[_]] ..]
Out[6]=
b[_] x[_] ..

You have to prevent this from happening with HoldPattern:

In[7]:=
Plus[x[1] b[1] , x[2] b[2] ] /. HoldPattern[Plus[Times[x[_], b[_]] ..] ] ->
z

Out[7]=
z

Andrzej
-- 
Andrzej Kozlowski
Toyama International University, JAPAN

For Mathematica related links and resources try:
<http://www.sstreams.com/Mathematica/>


on 6/10/00 4:00 PM, Johannes Ludsteck at ludsteck at zew.de wrote:

> Dear Group Members,
> I would like to "find" and replace expressions with the simple
> structure x[1] b[1]+x[2] b2]+...+x[n] b[n]
> I tried to use the following replacement rule
> In[27]:= x[1] b[1] + x[2] b[2] /. Plus[Times[x[_], b[_]] ..] -> z
> 
> Out[27]= b[1] x[1] + b[2] x[2] + b[3] x[3]
> Which didn't work (Out[27] should be z).
> Why?
> The following FullForm seems to give exactly the structure I used
> in my replacement rule.
> 
> In[17]:=
> FullForm[x[1] b[1] + x[2] b[2] + x[3] b[3]]
> Out[17]//FullForm=
> Plus[Times[b[1], x[1]], Times[b[2], x[2]], Times[b[3], x[3]]]
> 
> Even if this worked, my pattern wouldn't account for equal indices,
> i.e. it would match x[1] b[500]+x[12] b[3], even if it shouldn't.
> 
> Any suggestions?
> Thanks,
> Johannes Ludsteck
> 
> 
> Johannes Ludsteck
> Centre for European Economic Research (ZEW)
> Department of Labour Economics,
> Human Resources and Social Policy
> Phone (+49)(0)621/1235-157
> Fax (+49)(0)621/1235-225
> 
> P.O.Box 103443
> D-68034 Mannheim
> GERMANY
> 
> Email: ludsteck at zew.de
> 




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