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Re: PolarPlot question

• To: mathgroup at smc.vnet.net
• Subject: [mg25057] Re: PolarPlot question
• From: "Borut L." <JustMyName at email.si>
• Date: Thu, 7 Sep 2000 22:28:00 -0400 (EDT)
• References: <8ov0jn$9p8@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

Hi,

<<Graphics`Graphics`

r[fi_]:=16/(5+3 Cos[fi])
PolarPlot[r[fi],{fi,0,2 Pi}]

it works for me.



Doug Magnoli <dmagnoli at home.com> wrote in message
news:8ov0jn$9p8 at smc.vnet.net...
> I've defined:
>
> r[t] := 16/(5 + 3 Cos[t])
>
> Then I load Graphics, with:
>
> <<Graphics`
>
> and ask for: