MathGroup Archive 2000

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: PolarPlot question


Hi,

<<Graphics`Graphics`

r[fi_]:=16/(5+3 Cos[fi])
PolarPlot[r[fi],{fi,0,2 Pi}]

it works for me.



Doug Magnoli <dmagnoli at home.com> wrote in message
news:8ov0jn$9p8 at smc.vnet.net...
> I've defined:
>
> r[t] := 16/(5 + 3 Cos[t])
>
> Then I load Graphics, with:
>
> <<Graphics`
>
> and ask for:


  • Prev by Date: Re: Re: ListPlot
  • Next by Date: Mathematica 3.0 & MathReader 4.0
  • Previous by thread: Re: NotebookSave
  • Next by thread: Mathematica 3.0 & MathReader 4.0